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Boolean Operation

Polygon can be combined using boolean operation. The following boolean operation is supported :
let sq = square(10); let ci = circle(5).position(V2(7,0)); let result = boolean.union(sq, ci); draw(sq, ci, result.fill('lightblue'));
boolean.union ( d1  :  Diagram , d2  :  Diagram , tolerance?  :  number )  :  Diagram 
 

        let sq = square(10);
        let ci = circle(5).position(V2(7,0));
        
        let result = boolean.union(sq, ci);
        draw(sq, ci, result.fill('lightblue'));
         
 
 
 

        let sq = square(10)
            .stroke('gray').strokedasharray([5]);
        let ci = circle(5).position(V2(7,0))
            .stroke('gray').strokedasharray([5]);
            
        let result = boolean.difference(sq, ci);
        draw(sq, ci, result.fill('lightblue'));
         
 
boolean.difference  (
                d1
                             : 
                            Diagram , d2
                             : 
                            Diagram , tolerance?
                             : 
                            number )
                         : 
                            Diagram  
 

        let sq = square(10)
            .stroke('gray').strokedasharray([5]);
        let ci = circle(5).position(V2(7,0))
            .stroke('gray').strokedasharray([5]);
            
        let result = boolean.difference(sq, ci);
        draw(sq, ci, result.fill('lightblue'));
         
 
 
 

        let sq = square(10)
            .stroke('gray').strokedasharray([5]);
        let ci = circle(5).position(V2(7,0))
            .stroke('gray').strokedasharray([5]);
            
        let result = boolean.difference(ci, sq);
        draw(sq, ci, result.fill('lightblue'));
         
 
    
 

        let sq = square(10)
            .stroke('gray').strokedasharray([5]);
        let ci = circle(5).position(V2(7,0))
            .stroke('gray').strokedasharray([5]);
            
        let result = boolean.difference(ci, sq);
        draw(sq, ci, result.fill('lightblue'));
         
 
 
 

        let sq = square(10)
            .stroke('gray').strokedasharray([5]);
        let ci = circle(5).position(V2(7,0))
            .stroke('gray').strokedasharray([5]);
            
        let result = boolean.intersect(sq, ci);
        draw(sq, ci, result.fill('lightblue'));
         
 
boolean.intersect  (
                d1
                             : 
                            Diagram , d2
                             : 
                            Diagram , tolerance?
                             : 
                            number )
                         : 
                            Diagram  
 

        let sq = square(10)
            .stroke('gray').strokedasharray([5]);
        let ci = circle(5).position(V2(7,0))
            .stroke('gray').strokedasharray([5]);
            
        let result = boolean.intersect(sq, ci);
        draw(sq, ci, result.fill('lightblue'));
         
 
 
 

        let sq = square(10)
            .stroke('gray').strokedasharray([5]);
        let ci = circle(5).position(V2(7,0))
            .stroke('gray').strokedasharray([5]);
            
        let result = boolean.xor(sq, ci);
        draw(sq, ci, result.fill('lightblue'));
         
 
boolean.xor  (
                d1
                             : 
                            Diagram , d2
                             : 
                            Diagram , tolerance?
                             : 
                            number )
                         : 
                            Diagram  
 

        let sq = square(10)
            .stroke('gray').strokedasharray([5]);
        let ci = circle(5).position(V2(7,0))
            .stroke('gray').strokedasharray([5]);
            
        let result = boolean.xor(sq, ci);
        draw(sq, ci, result.fill('lightblue'));
         
 
* For all the boolean operations, there is an optional parameter tolerance which is used to determine the tolerance for the operation.
        The default value is 1e-10.